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3000=6x^2
We move all terms to the left:
3000-(6x^2)=0
a = -6; b = 0; c = +3000;
Δ = b2-4ac
Δ = 02-4·(-6)·3000
Δ = 72000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72000}=\sqrt{14400*5}=\sqrt{14400}*\sqrt{5}=120\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{5}}{2*-6}=\frac{0-120\sqrt{5}}{-12} =-\frac{120\sqrt{5}}{-12} =-\frac{10\sqrt{5}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{5}}{2*-6}=\frac{0+120\sqrt{5}}{-12} =\frac{120\sqrt{5}}{-12} =\frac{10\sqrt{5}}{-1} $
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